# VLSM, Subnetting Question

in CCNA

Hey guys,

so I was watching the videos and Keith gave this example:

Using this network:

140.140.0.0/22

create a subnetwork for 220 hosts, and another one for 45 hosts.

I know that going to /24 we can support 254 hosts. So Keith listed the network the following way:

140.140.0.0 and what is the max range here? He didn't provide the sample. And he moved on to the next network for 45 hosts this way:

140.140.1.0 to 140.140.1.63

My question is, why is it x.x.1.0??? How does this work? Can someone please break it down for me.

Also, what's the max range for this network for 254 hosts with a subnet mask of /24? Is it 10.140.255.254? I'm lost here.

Please help!!

Thanks

Chris

0

## Comments

Find other video(s) about VLSM that explains it if one u watching now does not work for you. also, you must know inside/out regular subnetting before going into VLSM.

so, 2 networks, one with 220 hosts, and one for 45 hosts.

140.140.0.0 - 140.140.3.255 is the range u can work with for /22.

220 falls into group 254, 8 bit used up, aka /24

140.140.0.0/24 is used up for 1st network with 220 hosts. Range 140.140.0.1 - 0.254; B-caast 0.255

next up is 140.140.1.0. 45 falls into 64 block, /26 which gives u 62 hosts. starting where u ended up, range is

140.140.1.0 to 140.140.1.63. next up is 140.140.1.64/26, then would be x.x.1.128, then x.x.1.192. then , if u continue with 63 hosts (block of 64), network x.x 2.0, xx.2.64, x.x2.128, xx.2.192. finally, x.x.3.0 thru 3.255 is your last range since u have /22 to begin in first place.

if u would need 2 networks for 220 hosts, then for 45 hosts, answer would be:

140.140.0.0/24

140.140.1.0/24

140.140.2.0/26

next range available is 140.140.2.64/26.

see my magic table below

Hey Martini,

Thanks for clearing this up. I've actually been doing a lot of subnetting practice since I made this post and now I got it down. Your answer made it even clearer and I appreciate that. Your breakdown made things even simpler, I feel more confident doing these problems now.

Thank you.

no problem