Redistribution problem !
I'm currently studying about redistribute problem between OSPF and EIGRP.
Let's take this topology as an example !
On R1 I did redistribute connected.
R1 R2 R3 using EIGRP. R2, R3 Using OSPF
I did redistribute EIGRP into OSPF on R2.
So, stand at R3, It will go to R2 -> R1 and Lo 0 which is 10.0.0.0.
But nothing about OSPF external route E2 show up in R3 topology table.
Link between R1-R2 126.96.36.199 ; R1-R3 188.8.131.52; R2-R3 184.108.40.206 .
The output from R3 :
R3#sh ip route
Codes: C - connected, S - static, R - RIP, M - mobile, B - BGP
D - EIGRP, EX - EIGRP external, O - OSPF, IA - OSPF inter area
N1 - OSPF NSSA external type 1, N2 - OSPF NSSA external type 2
E1 - OSPF external type 1, E2 - OSPF external type 2
i - IS-IS, su - IS-IS summary, L1 - IS-IS level-1, L2 - IS-IS level-2
ia - IS-IS inter area, * - candidate default, U - per-user static route
o - ODR, P - periodic downloaded static route
Gateway of last resort is not set
220.127.116.11/24 is subnetted, 3 subnets
D 18.104.22.168 [90/30720] via 22.214.171.124, 00:31:27, FastEthernet0/0
[90/30720] via 126.96.36.199, 00:31:27, FastEthernet0/1
C 188.8.131.52 is directly connected, FastEthernet0/0
C 184.108.40.206 is directly connected, FastEthernet0/1
10.0.0.0/24 is subnetted, 1 subnets
D EX 10.0.0.0 [170/156160] via 220.127.116.11, 00:28:47, FastEthernet0/0
Can anyone tell me why ? Thanks !
Why R3 doesn't take The path R3-R2-R1-> Lo0 ( The OSPF path which external AD = 110 ), but it takes the Path R3-R1-Lo0 ( The EIGRP redistribute connected path which AD = 170 ) ? I think it supposed to take the R3-R2-R1-Lo0 As the book said. !