QOS - Question

Hi Guys,

 

What does it mean when the SG says : "The Frame Relay circuit between R2 and R4 has been provisioned at 512Kbps "

Does that mean circuit at each side has a CIR of 512 kbps ? What about the access rate in order to get Be ?

 

THanks

Comments

  • Hi Guys,

     

    What does it mean when the SG says : "The Frame Relay circuit between R2 and R4 has been provisioned at 512Kbps "

    Does that mean circuit at each side has a CIR of 512 kbps ? What about the access rate in order to get Be ?

     

    THanks

     

    Hi,

    This means that the CIR is 512 Kbps, which is the committed information rate that the provider is commited to transmit. For Frame-Relay in INE's WB, the access rate is usually a T1 Serial interface, which is ~1.5. So that means that your CIR is lower than your AR and you should do some sort of traffic-shaping in order to be in accordance to the CIR of the provider, which will be doing some sort of policing on their side.

    You could do a map-class and apply traffic-shaping to the CIR or use MQC to perform traffic-shaping.

    HTH

    Good luck!

     

  • So assuming the access rate is T1 (1536 kbps) , this means:

    Be = (1536 - 512 ) x Tc

     

    Is that correct ?

     

  • Hi Guys,

    What does it mean when the SG says : "The Frame Relay circuit between R2 and R4 has been provisioned at 512Kbps "

    Does that mean circuit at each side has a CIR of 512 kbps ? What about the access rate in order to get Be ?

    THanks

    The requirement asks you to have CIR 512Kbps out of the Access Rate of 1544Kbps. 

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