Lab 3 Task 4.12

I am using ver 4.11.

When I summarize the loopback address on the fa0/0 interface with the following command, why do I get a 150.1.8.0/23 route in the routing tables of the routers on this segment instead of a 150.1.9.0/23 route?

ip summary-address eigrp 10 150.1.9.0 255.255.254.0

I've tried to logically figure it out bit-wise, but it doesn't make sense to me.

Comments

  • Acer0001,

    When you summarize 150.1.9.0 to /23, the first 23 bits are the summary: 150.1.8.0. The 3rd octet is 00001000 (8). In order to have a 9 in the third octet (00001001), you would need a 24-bit summary (/24). Both 150.1.8.0 and 150.1.9.0 fall within the /23 summary.

    Darrell
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